A moving block having mass 
, collides with another stationary block having mass 4 m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is 
, then the value of coefficient of restitution (e) will be [NEET 2018]
Text Solution
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Since, the collision mentioned is an elastic head-on collision. Thus, according to the law of
conservation of linear momentum, we get
where, 
and 
are the masses of the two blocks and 
and 
are their initial velocities and 
and 
are their final velocities, respectively.
Here, 
As, the coefficient of restitution is given as
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